Brody Smithson was a major factor in Brookwood's victory over Paul W. Bryant on Tuesday. Smithson turned in his biggest game of the season, going 1-for-3 with one home run and two RBI. That home run marked the first that he launched this season.
Smithson's strong effort led Brookwood over Paul W. Bryant and he'll get a chance to do so again: the teams have a rematch scheduled at 5:00 p.m. on Thursday. The Stampede are limping into the matchup having lost four straight at home. There's no doubt they're looking for a change of fortune, but will Smithson and the Panthers have enough to stop it? Check back here after the action for a full breakdown and analysis of the contest.
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