The Seymour Indians will square off against the Mendon Unity Mustangs at 4:30 p.m. on Friday. Seymour is coming into the contest on a four-game losing streak.
Seymour fell victim to Pittsfield and their airtight pitching crew on Thursday. They lost 10-0 to the Saukees. While getting shut out isn't ideal, the Indians haven't been shut out since back in March.
Meanwhile, Mendon Unity got the win against Rushville-Industry on Monday by a conclusive 12-2. The result was nothing new for the Mustangs, who have now won five matchups by seven runs or more so far this season.
Avery Frese was a major factor no matter where he played. On the mound, he struck out eight batters over five innings while giving up just two earned runs off six hits (and only one walk). That's the most strikeouts he has posted since back in March. He was also solid in the batter's box, going 1-for-2 with three RBI and one run.
In other batting news, the team relied heavily on Henry Bealor, who went a perfect 2-for-2 with one home run and two RBI. Those two RBI gave him a new career-high. Jayce Huntley was another key player, going 2-for-3 with two runs and two RBI.
Mendon Unity kept the outfield on their toes and finished the game with 13 hits. They are 5-1 when they post 11 or more hits.
Mendon Unity's victory bumped their record up to 9-7. As for Seymour, their loss dropped their record down to 8-12.
Seymour couldn't quite get it done against Mendon Unity in their previous meeting back in March as they fell 7-2. Will the Indians have more luck at home instead of on the road? Check MaxPreps after the action for a full breakdown of the game and more baseball content.
Article generated by infoSentience based on data entered on MaxPreps
